Based on the third arrangement of the labyrinths from the last post (see: related posts, below) the transpose and complementary labyrinths can be directly, and the dual labyrinth can be indirectlycalculated quite simply. For this, the sequence of circuits of the base labyrinth is needed.
Here, I want to exercise this with the example of the labyrinth depicted in fig. 1.
The labyrinth is situated with the entrance on top and in anti-clockwise rotation. First, I redraw it such that the entrance lies at the bottom and the labyrinth rotates clockwise. By this, it presents itself in the form I always use for a comparison of labyrinths. This labyrinth with one axis and 9 circuits will serve as our base labyrinth. Its sequence…
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